Bacsinszky, Lisicki to clash in Luxembourg final

Switzerland's Timea Bacsinszky will on Sunday attempt to win her first WTA tour title when she faces German sixth seed Sabine Lisicki in the final of the 222,000-dollar Luxembourg Open.

Switzerland's Timea Bacsinszky will on Sunday attempt to win her first WTA tour title when she faces German sixth seed Sabine Lisicki, pictured here in action in September 2009, in the final of the 222,000-dollar Luxembourg Open.

Bacsinszky, the world number 70, put out Belgian fifth seed Yanina Wickmayer, last week's Linz champion, 3-6, 6-2, 7-5.

Lisicki, meanwhile, saw off Israel's Shahar Peer 6-3, 4-6, 7-6 (7/5) in a 2hr 20min semi-final marathon.

Tournament favourites, US Open winner Kim Clijsters and Danish world number six Caroline Wozniacki, were eliminated earlier in the tournament.